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The "Triple Product of Cross Products" IdentityKatie writes, Prove that (u cross v) dot ( (v cross w) cross (w cross u) ) = (u dot (v
cross w) )2
My first thought on seeing this is "what a mess!" But as the cobwebs cleared, I noticed the left side is a triple product, so maybe it's the volume of a parallelepiped. The three vectors being multiplied together are the three cross products of u, v, and w, or the "directed areas" of the three faces that meet at one corner. Triple CrossProof that (u×v)·((v×w)×(w×u)) = (u·(v×w))2 Let's start by looking at the cross product (v×w)×(w×u). v×w is perpendicular to w, and so is w×u perpendicular to w, so it follows that when you cross these two vectors, both perpendicular to w, the resulting cross product is a scalar multiple of w. This thinking is confirmed, when, by Lagrange's Formula, a×(b×c) = (c·a)b - (b·a)c, it follows that
Because w and v×w are orthogonal w·(v×w)=0, so the formula simplifies to
which I put in bold face, because it's a fairly useful fact in its own right. (Another way to get this result is from the general formula for the cross product of two cross products, in which the second determinant is zero.) If we let "a" represent the scalar triple product, a = u·(v×w), we see from the bold-face formula, above, that
and so, because a = u·(v×w) = w·(u×v),
Cross Product of Two Cross ProductsIf a, b, c, and d are vectors, then the cross product of a×b and c×d is given by
where det is the determinant of the square matrix formed by placing the three vectors, one above the other. Internet ReferencesRelated Pages in this website
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