Proof: take a to be any positive integer coprime to p.
Consider the set {a, 2a, 3a, ..., (p-1)a}.
No two elements of this set are congruent mod p (see below*), so their residues mod p must
be {1, 2, 3, ..., p-1} in some order.
By equating the product of the numbers in the first set with the product of
those in the second set, mod p,
ap-1(p-1)! = (p-1)! (mod p)
Since (p-1)! is coprime to p, we can divide both sides by (p-1)!, mod p, proving
Fermat's Little Theorem.
* Why are no two elements of {a, 2a, 3a, ..., (p-1)a} congruent, mod p?
Suppose a is a number coprime to p, and b and c are two different numbers in
the range [1,p-1] and ab=ac, mod p.
Then ab-ac=pk, where k is an integer.
a(b-c)=pk, and since b-c is smaller than p in absolute value, a must be larger
than k in absolute value.
a and p have no factors in common, so a|k, but a can't divide k, since a is
larger than k, a contradiction.
Euler's criterion for
determining whether a number is a quadratic residue (mod p), or in other
words, if a number is the square of some other number (mod p).
Proof of Fermat's Last
Theorem for n=3, attributed to Euler
Proof that there is no solution to the Diophantine equation
A4+B4=C2, which means Fermat's last theorem
is true for n=4.
Squares.
Euler's Totient Theorem -- a
generalization of Fermat's Little Theorem
The proof that primes of the form 4k+3 can be expressed as the sum of four squares
uses Fermat's Little Theorem.
Group - a set closed under one operation.
A bunch of Ring Theory theorems and
definitions.