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Unsolved Problem 36: prove nn+1 is not prime when n > 4It seemed that this problem was solved, as the following flawed "proof" (from www.spiritual-coder.com/primepowers/) was offered. Though it narrows down the possible values of n considerably, it doesn't prove every case. In particular, it is not known whether there are more than five Fermat primes. Theoremnn+1 is never a prime number if n > 4. Preliminary remarkAll
variables used below are positive integers. ProofCase I: n is not a power of 2 If n is not a power of 2, it can always be written as (2m+1)p, where m and p are positive integers. Then nn+1 = (((2m+1)p)p)(2m+1)+1 which is a multiple of ((2m+1)p)p+1 because of this factorization: x(2n+1)+1 = (x+1)(x2n - x2n-1 + ... + x2 - x + 1) Case II: n is a power of 2 Then nn+1 = (2p)(2^p)+1 = 2(p 2^p)+1 Case IIa: p is not a power of 2 If p is not a power of 2, it can always be written as (2k+1)t, where k and t are positive integers. Then, as in Case I, above, there is one plus a number raised to an odd power, which can be factorized: nn+1 = (2(t2^p))(2k+1)+1 which is a multiple of 2(t2^p)+1 Case IIb: p is a power of 2 p is a power of 2, then p=2q. Rewriting nn+1=(2p)(2^p)+1 results in the expression 2(2^(q+2^q))+1 Putting r=q+2q we recognize the expression as the Fermat number Fr. For q=0 we have F1 = 5 and n=2, thus nn+1=5 which is prime. For q=1 we have F3 = 257 and n=4, thus nn+1=257 which is prime. For q > 1 we have Fermat numbers Fr with r = 6, 11, 20, 37, ... which all have a divisor of the form 2(r+1)L+1 with L integer (proven by Lucas in 1878 - see Mathworld: Fermat Number). Alas, it is not known whether 2(r+1)L+1 is the only factor of some Fermat number thus making it prime. Originally, the proof concluded that also in the case IIb nn+1=2(2^(q+2^q))+1 is not a prime for q > 1. Final conclusion:It has been shown in all but a small (but infinite) number of cases that nn+1 for n > 4 is never a prime. The original "proof", upon which this page is based, is copyright © Bernard Jacobs – 16 March 2004, and used here with attribution under the "fair use" exception to copyright law. Internet References
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